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8a^2-1000=0
a = 8; b = 0; c = -1000;
Δ = b2-4ac
Δ = 02-4·8·(-1000)
Δ = 32000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32000}=\sqrt{6400*5}=\sqrt{6400}*\sqrt{5}=80\sqrt{5}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{5}}{2*8}=\frac{0-80\sqrt{5}}{16} =-\frac{80\sqrt{5}}{16} =-5\sqrt{5} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{5}}{2*8}=\frac{0+80\sqrt{5}}{16} =\frac{80\sqrt{5}}{16} =5\sqrt{5} $
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